To what extent can mathematical simplification be regarded as the final result? For mathematical simplification and evaluation, to what extent can it be regarded as the final result? For example, is the result a fraction or a decimal? A fraction or a sum of fractions? And so on I remember when I went to school, the teacher emphasized I'd like to know the requirements for the final result

To what extent can mathematical simplification be regarded as the final result? For mathematical simplification and evaluation, to what extent can it be regarded as the final result? For example, is the result a fraction or a decimal? A fraction or a sum of fractions? And so on I remember when I went to school, the teacher emphasized I'd like to know the requirements for the final result

A combination of terms that can be combined into fractions. Fractions with letters are arranged according to the unified ascending or descending power
But at the same time, special circumstances should also consider the beauty of the answer
In general, there is no need to deliberately consider the output form, the right is the ultimate goal
The results of simplification and evaluation must be accurate and the simplest
If it can't be reduced to a finite number, use fractions. If it can, use decimals
The fraction should be reduced to the simplest and single fraction. If it is not a polynomial, it should be reduced to a fraction (it must be irreducible), and it can be divided into decimals
If it is a polynomial, it should be combined according to the number of items and arranged in order. The requirements for the results of junior high school mathematics are generally to be simplified to the point where they cannot be reduced, that is, the results are in the form of monomials, polynomials or fractions, When there is no requirement, any form is OK. Generally, keep the score form as far as possible

4 / X-2 + X + 2 / 2-x is a fraction, which is 4 / 2 of X-2,

4/(x-2)+(x+2)/(2-x)
=4/(x-2) -(x+2)/(x-2)
=(4-x-2)/(x-2)
=(2-x)/(x-2)
= -(x-2)/(x-2)= -1

In triangle ABC, three sides are ABC, and a = 2m & sup2; + 2m, B = m + 1, C = 2m & sup2; + 2m + 1
There must be a complete process, so that I can understand. Some people ask such questions, but the answers are not comprehensive. I hope you can answer them seriously!

B is 2m + 1
c²-a²
=(c+a)(c-a)
=(2m²+2m+1+2m²+2m)(2m²+2m+1-2m²-2m)
=(4m²+4m+1)*1
=(2m+1)²
=b²
So a & sup2; + B & sup2; = C & sup2;
So it's a right triangle

It is known that a, B and C are the three sides of △ ABC and satisfy A2 (c2-a2) = B2 (c2-b2). The shape of the triangle is determined

∵ a, B, C are the three sides of △ ABC, ∵ a ＞ 0, B ＞ 0, C ＞ 0. ∵ A2 (c2-a2) = B2 (c2-b2), ∵ a2c2-a4-b2c2 + B4 = 0, then (A2-B2) (A2 + B2) - C2 (A2-B2) = 0, ∵ (A2-B2) (A2 + b2-c2) = 0, ∵ A2-B2 = 0, A2 + b2-c2 = 0 ∵ A2 = B2, A2 + B2 = C2, ∵ a = C, ∠ C = 90 °, and ∵ ABC is an isosceles triangle or a right triangle