Solve the equations: 2x + y = 15,2x-3y = - 1

Solve the equations: 2x + y = 15,2x-3y = - 1

2x+y=15 (1),
2x-3y=-1 (2)
(1)-(2)
4y=16
y=4
Substitute (1) to get
2x=15-4
x=5.5

To solve the equations: {x + | 3x-y | + 3Y = 15 2x + y = 6
To solve the equations: {x + | 3x-y | + 3Y = 15 ① {2x + y = 6 ②

If 3x > y, the equations are contradictory, so 3x < y, the solution is x = 9 / 10, y = 21 / 5

Finding the integer solution of the system of equations 2x + 3Y = 15
Finding positive integer solutions of equations 2x + 3Y = 15

2x+3x=15 5x=15 x=15/5 x=3

Solving the system of linear equations with two variables 5x + 3Y = 52x-3y = 23
5X+3Y=5
2X-3Y=23
10X+3Y=-131
X-5Y=24

5X+3Y=5
2X-3Y=23
Add it up to 7x = 28
So x = 4, y = - 5
10X+3Y=-131
X-5y = 24, that is, 10x-50y = 240
By subtracting, we get 53Y = - 371
y=-7,x=-11