Y = lgx > 1 y range?

Y = lgx > 1 y range?

Y = lgx is a monotone increasing function
When x = 1, y = LG1 = 0
So when x is greater than 1
y＞0

If lgx + lgx2 + lgx3 + +If lgx10 = 110 (x > 0), then lgx + lg2x + lg3x + +The value of lg10x is 3Q
This is a mathematical problem. I can't find the classification of mathematics, so I put it here. The problem is in the paper of this chapter. It's a process to know the answer

55lgx=110,lgx=2 （10lgx）+lg（1*2*3*4*5*6*7*8*9*10）=20+lg（1*2*3*4*5*6*7*8*9*10）

If lgx + lgx2 + lgx3 +... + lgx99 = 9900, then lgx100=

That is: lgx + 2lgx + 3lgx +... + 99lgx = 9900
That is: (1 + 2 + 3 +... + 99) lgx = 9900
4950lgx=9900 lgx=2
Then lgx100 = 100lgx = 200
PS: is lgx2 LG (the second power of x)