How to solve the inequality where the square of 2x minus 2x plus 1 is greater than 4x minus x

How to solve the inequality where the square of 2x minus 2x plus 1 is greater than 4x minus x

4(2x^2-2x+1)>x(4-x)
8x^2-8x+4>4x-x^2
9x^2-12x+4>0
(3x-2)^2>0
∴x≠2/3
(∵ (3x-2) ^ 2 is a non negative number, and (3x-2) ^ 2 > 0
∴x≠2/3)

The solution set of the inequality system (M & # 178; + 1) x ＞ M & # 178; + 1 of X is

(m^2+1)x>m^2+1
(m^2+1)(x-1)>0
Because m ^ 2 + 1 > = 1
So (m ^ 2 + 1) (x-1) > 0 can be changed into
x-1>0
x>1
So the solution set of inequality is {x | x > 1}

If M ＜ n, then the inequality (m-n) x ＞ M-N becomes "x ＞ a" or "x ＜ a" in the form of______ ．

∵ m ＜ n, ∵ M-N ＜ 0, ∵ inequality (m-n) x ＞ M-N, divided by (m-n) on both sides, we get x ＜ 1. So the answer is: X ＜ 1