(2x-3) (2x + 3) = the square of AX + BX + C to find a = b = C=

(2x-3) (2x + 3) = the square of AX + BX + C to find a = b = C=

(2x-3)(2x+3)
=(2x)²-3²
=4x²-9
a=4
b=0
c=-9

If ax ^ 2 + BX + C = (2x-1) (x + 3), then a = (), B = (), C = ()

Ax ^ 2 + BX + C = (2x-1) (x + 3), then a = (2), B = (5), C = (- 3)

Given that f (x) = AX2 + BX is an even function defined on [A-1, 2A], then the value of a + B is ()
A. −13B. 13C. −12D. 12

According to the meaning of the title: F (- x) = f (x), B = 0, and A-1 = - 2A, a = 13, a + B = 13

It is known that f (x) = ax ^ 2 + BX + C (2a-3)

Even function, so the domain is symmetric about the origin,
-2a-3 = 1, so a = - 1
And because it is an even function, the axis of symmetry of the function is x = 0
-B / 2A = 0, B = 0