When AB is greater than 0 and AC is less than 0, which quadrant can't the straight line ax + by + C = 0 pass through?

When AB is greater than 0 and AC is less than 0, which quadrant can't the straight line ax + by + C = 0 pass through?

The linear deformation is y = - (A / b) x-C / b
AB > 0 {indicating that a and B have the same sign} then - A / B0, then the image passes through 1,2,3 quadrants k > 0, B

If a is greater than 0, B is greater than 0, and C is less than 0, then the line ax + by + C equals 0, which quadrant must pass

Ax+By+C=0
By=-Ax-C
y=-(A/B)x-(C/B)
∵A>0,B>0,C

If A.C

Y = - (A / b) x - (C / b) because AC ＜ 0, BC ＜ 0, then AB is the same sign, then the coefficient K in front of x = - (A / b) ＜ 0, the line passes through 2,4 quadrants, and
If BC < 0, then - (C / b) > 0, then when x = 0, Y > 0, so the line passes through quadrants 1,2,4,

If AC < 0, BC < 0, then the line ax + by + C = 0 does not pass through which quadrant

ac0
So AB > 0
So a / b > 0
-a/b