Red eye is dominant to white eye in Drosophila melanogaster, and the gene controlling this pair of traits is located on X chromosome. Drosophila melanogaster can survive and reproduce normally without one chromosome IV, and die if two chromosomes are missing A. 14 B. 14 C. 14 d. 14 C. 14 d. 14 C. 14 C. 14 d. 14 d. 14 C. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d

Red eye is dominant to white eye in Drosophila melanogaster, and the gene controlling this pair of traits is located on X chromosome. Drosophila melanogaster can survive and reproduce normally without one chromosome IV, and die if two chromosomes are missing A. 14 B. 14 C. 14 d. 14 C. 14 d. 14 C. 14 C. 14 d. 14 d. 14 C. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d. 14 d

A. In xby × XbXb, white eyed male Drosophila accounted for 14, a was correct; in B, xby × xbxbxb, red eyed female Drosophila accounted for 12, B was wrong; in C, IV, female Drosophila accounted for 12, B was wrong_ XBY×Ⅳ_ XbXb, the number of Drosophila melanogaster with normal chromosome IV is 13, the number of Drosophila melanogaster with red eye is 34, so the number of Drosophila melanogaster with normal chromosome number is 13 × 34 = 14, C is correct; D, the number of Drosophila melanogaster with missing chromosome IV is 14 × 23 = 16, D is wrong

(2006. The first mock exam in Fengxian District) the grey body and black body of known fruit flies are a pair of relative traits. The gene is located on the autosomal chromosome. The hybrid of the pure fruit fly and the black body Drosophila is F1. The F1 is free to mate and produce F2. The fly of F2 is removed and allowed to mate freely. The proportion of the grey body and the black body Drosophila in the offspring is ().
A. 1：1B. 2：1C. 3：1D. 8：1

According to the law of genetic balance, the genotype and proportion of Drosophila melanogaster in F1 progeny are AA: AA: AA = (23 × 23): (2 × 13 × 23): (13 × 13) = 4:4:1, so the proportion of Drosophila melanogaster and Drosophila melanogaster in offspring is 8:1

The figure shows a cell of Drosophila, in which the number represents chromosome and the letter represents gene
A. From the perspective of chromosomes, the Drosophila can only form one gamete. The probability of occurrence of B. E gene controlled traits in male and female individuals is equal. C. the free combination of genes a, a, B and B during gamete formation. D. when only two pairs of chromosomes 3, 4, 7 and 8 are considered, the individual can form four kinds of gametes, and the number of gametes is equal

A. In terms of chromosome, the Drosophila melanogaster is a male Drosophila melanogaster, so it can form 8 kinds of gametes, a error; B, E genes are located on the X chromosome, and there is no allele on the Y chromosome, so the probability of occurrence of traits controlled by E gene in male individuals is higher than that in female individuals, B error; C, a

The chromosome diagram of a fruit fly is shown in the figure. The number of gamete species with different gene composition is ()
A. Three species B. four species C. six species D. eight species

As can be seen from the figure and meiosis, there are four types of gametes, including three autosomes and one sex chromosome, namely: X, II, III (EF), IV or Y, II, III (EF), IV; X, II, III (EF), IV or Y, II, III (EF), IV. as shown in the figure, B