As shown in figure 1-4-11, it is known that the perimeter of the quadrilateral ABCD is 25cm, and the distance between the opposite sides is de = 2cm and DF = 3cm respectively. Calculate the area (cm2) of the parallelogram

Let length be x and width be y
2X equals 3Y
2X + 2Y equals 25
Find that x is 7.5 and Y is 5
So the area is 15

If the perimeter of the parallelogram is 25cm and the distance between the opposite sides is 2cm and 3cm respectively, the area of the parallelogram is ()
A. 15cm2B. 25cm2C. 30cm2D. 50cm2

∵ the distance between the two opposite sides of a parallelogram is 2cm and 3cm, respectively; the ratio of the shorter side to the longer side of a parallelogram is 2:3; the perimeter of a parallelogram is 25cm; the shorter side of a parallelogram is 5cm and the longer side is 7.5cm. Then the area of a parallelogram is 5 × 3 = 15 (cm2)

It is known that the perimeter of the parallelogram ABCD is 24 cm, and the distance between the opposite sides is de = 2 cm and DF = 3 cm respectively. Find the area of the parallelogram

Let both sides be x and Y respectively, then 2x = 3Y, and X + y = 12, calculate X and y, and you can get the area

If the circumference of isosceles trapezoid is 80cm, the median line length is equal to the waist length, and the height is 12cm, then its area is______ cm2．

Let the median line length of the trapezoid be xcm, then the sum of the upper bottom and the lower bottom is 2xcm. From the meaning of the question, 2x + X + x = 80, the solution is x = 20, so the area of the trapezoid is 20 × 12 = 240cm2

The circumference of an isosceles trapezoid is 80cm, the waist length is 15cm, and the height is 12cm

Area of trapezoid = (80-15x2) X12 / 2 = 300
The area of this trapezoid is (300) square centimeters

The perimeter of an isosceles trapezoid is 80cm. If its median line is equal to the waist length and its height is 12cm, then the area of the trapezoid is______ cm2．

Let the median line length of isosceles trapezoid be x, then the waist length is x, the sum of the upper and lower bottom is 2x, and the circumference of isosceles trapezoid is 2x + X + x = 80. The solution is x = 20, so the area of this trapezoid is 20 × 12 = 240cm2

It is known that the circumference of isosceles trapezoid is 80cm, and the median line length is equal to the waist, then the median line length of isosceles trapezoid is equal to the waist______ cm．

Because the median line of the trapezoid is equal to half of the sum of the upper bottom and the lower bottom, and because the median line length is equal to the waist, the median line length of the trapezoid is equal to 12 × 12 × 80 = 20cm

What is the circumference of a rectangle?

(L + W) * 2 = perimeter of rectangle

How to calculate the circumference of a rectangle?

Multiply the sum of the short and long sides by 2

The circumference of a rectangle is equal to 60cm, and its unequal edge difference is 20cm. Find the lengths of the rectangle (using the linear equation of one variable)

Let YCM be the width and 20 + YCM be the length
(y+20+y)x2=60
4y=20
y=5
5+20=25cm

As shown in figure 1-4-11, it is known that the perimeter of the quadrilateral ABCD is 25cm, and the distance between the opposite sides is de = 2cm and DF = 3cm respectively. Calculate the area (cm2) of the parallelogram