It is known that the circumference of a rectangle is 60cm, and the length is 20cm more than the width. Let the length of a rectangle be xcm and the width be YCM, and the binary linear equations about X and y are listed

It is known that the circumference of a rectangle is 60cm, and the length is 20cm more than the width. Let the length of a rectangle be xcm and the width be YCM, and the binary linear equations about X and y are listed

x-y=20
2x+2y=60

The circumference of a rectangle is equal to 60cm, and its length is 10cm more than its width. The detailed equations of its length and width are obtained

Let the length be X
The width is X-10
2*（x+x-10)=60
x=20

The circumference of a rectangle is 60cm, and its length is four times of its width. Find its area

Width = 60 ／ 2 ／ (1 + 4) × 1 = 6cm
Length = 6 × 4 = 24cm
Area = 24 × 6 = 144cm & sup2;

Fangfang was at the bottom of a pagoda and found a note telling her how many steps she had to climb to get a treasure map: "bigger than 125, smaller than 180; five, five places,
The following is: no surplus; it's a multiple of 4 and 8?

5x4x8=160
So it's 160 steps!

Fangfang is on the lower floor of a pagoda. She finds a note telling her how many steps she has to climb to get a treasure map. It's bigger than 125 and smaller than 180. It's five and five

This is the sixth grade winter vacation homework, right~
The meaning of this problem is to find the common multiple of 5, 4 and 8 between 125 and 180
4. The greatest common divisor of 8 is 4
therefore
5. The least common multiple of 4 and 8 is 5 × 4 × 8 △ 4 = 40
40×1=40
40×2=80
40×3=120
40×4=160
40×5=200
…
Between 125 and 180, there are only 160. So Fangfang can find the treasure map only by climbing 160 steps
This is the sixth grade winter vacation homework problem ~ we will report tomorrow, you can do it?

Mingming and Liangliang have a total of 896.5 yuan. The decimal point of Mingming's money moves one place to the left, which is as much as Liangliang's money. How much do they each have?

896.5 ^ (10 + 1) = 896.5 ^ 11 = 81.5 (yuan) 81.5 × 10 = 815 (yuan) answer: there is 815 yuan for Mingming and 81.5 yuan for Liangliang

Fangfang and Mingming buy the same kind of toys. The price of the toys is 3 / 5 of Fangfang's total money, which is 1 / 3 of Mingming's total money. After they all buy the toys, Fangfang has the rest

If we regard the price of toys as 1, then Fangfang's money is 1 / 3 / 5 = 5 / 3, clearly all the money is 1 / 2 / 3 = 3 / 2
The price of the toy is 10 (5 / 3-3 / 2) = 60 yuan
All the money of Fangfang is 60 / 3 / 5 = 100 yuan
So Fangfang's remaining money is 100-60 = 40 yuan

Yuanyuan said to Fangfang: as long as you give me 100 yuan, my money will be twice as much as you. Fangfang said: as long as you give me 10 yuan, my money will be five times more than you, yuan
Please use formula instead of equation

The solution is as follows:
1. Yuanyuan said to the other party, "if you give me 100 yuan, my money will be twice as much as yours." it means that the total amount of money is three times of (fangfang-100)
2. Fang Fang said to Yuanyuan, "as long as you give me 10 yuan, my money will be five times more than you."
3. The total amount of money is 3 times of (fangfang-100) and 7 times of (yuanyuan-10), so the total amount of money can be regarded as 3 * 7 = 21. (fangfang-100) accounts for 7 of the total amount of money, (yuanyuan-10) accounts for 3 of the total amount of money. (fangfang-100) and (yuanyuan-10) total 10
4. So (100 + 10) is equivalent to (21-10) shares, and (100 + 10) / (21-10) = 10 yuan
5. Yuanyuan: 10 * 21 / 7 + 10 = 40 yuan; Fangfang: 10 * 21 / 3 + 100 = 170 yuan

A rectangular biscuit box is 17 cm long, 11 cm wide and 22 cm high. If a circle of brand paper is pasted on its side, how many square meters is the area of this brand paper at least

If one circle is attached on the side, the area is bottom perimeter × height = (17 + 11) × 2 × 22 = 1232cm & # 178;
So we need at least 1232cm and 178; of brand paper
Do not understand, please continue to ask yo~

Given that the lengths of two sides of a triangle are 3cm and 4cm respectively, the value range of the third side length x is
If x is odd, what is the value of X? How many triangles are there? If x is even?

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