The two right sides of a right triangle are 6 and 8, and the three sides of a right triangle are the diameters of the three semicircles

The two right sides of a right triangle are 6 and 8, and the three sides of a right triangle are the diameters of the three semicircles

From Pythagorean theorem: the third side is 10
6÷2=3,8÷2=4,10÷2=5
Let the PI be 3.14
3×3×3.14+4×4×3.14+5×5×3.14=157
So the shadow area is 157
A: the shadow area is 157

As shown in Figure 2, the lengths of the two right angles of the right triangle are 6 and 8 respectively, so the area of the shadow part in the figure is

Although there is no graph, it should be s triangle ABC = 6 * 8 * 1 / 2 = 24

If the length of the two diagonals of a parallelogram is 8 and 14 respectively, the value range of the side length x of the parallelogram is?

The diagonals of parallelograms are bisected
So half of the diagonal is 4 and 7
Let the side length of a parallelogram be a
7-4

It is known that the length of one side of a parallelogram is 12, and the length of its two diagonals may be ()
A. 8 and 14b. 10 and 14C. 18 and 20d. 10 and 34

A. If half of the two diagonals are 4, 7, ∵ 4 + 7 = 11 < 12, ∵ can not form a triangle, so this option is wrong; if half of the two diagonals are 5, 7, ∵ 5 + 7 = 12, ∵ can not form a triangle, so this option is wrong; if half of the two diagonals are 9, 10, ∵ 9 + 10 = 19, ∵ can form a triangle, so this option is correct; if half of the two diagonals are 5, then this option is wrong , 17, ∵ 5 + 12 = 17, ∵ can't form triangle, so this option is wrong

The diagonals of parallelogram are x and Y respectively. If one side is 12 long, the values of X and Y may be A8 and 14b10 and 14c18 and 20d10 and 28

½x-½y＜12＜½x+½y
C18 and 20 are eligible

If the length of one side of a parallelogram is 10, the length of its two diagonals can be (). A.4 and 6 B.6 and 8 c.8
If the length of one side of a parallelogram is 10, the length of its two diagonals can be (). A.4 and 6 B.6 and 8 c.8 and 12 d.20 and 30

D
The parallelogram is connected diagonally and divided into four triangles

The perimeter of a parallelogram is 82cm, the bottom of one parallelogram is 16cm, and the height of this parallelogram is 20cm. Find the height of the other parallelogram

The length of the other base = (82-2 × 16) △ 2 = 25cm
Parallelogram area = 16 × 20 = 320 square centimeter
Height on the bottom of the other one = 320 △ 25 = 12.8 cm

The perimeter of a parallelogram is 82 cm, the length of a bottom edge is 16 cm, and the height of this edge is 20 cm

"It's about the height of the other side," right?
The other side length is: 82 / 2-16 = 25 cm
The area of this flat quadrilateral is: 16 * 20 = 320 square centimeters
The height of the other side is: 320 / 25 = 12.8 cm

(1) It is known that the lengths of the three segments are 10, 14 and 20 respectively. Taking two of them as diagonals and the other one as edges, several parallelograms can be drawn
(2) It is known that the lengths of three line segments are 7, 15 and 20 respectively. Taking one of them as diagonal and the other two as adjacent sides, several parallelograms can be drawn

(1) If 10,14 is diagonal and 20 is one side, then 5 + 7 = 1214 can be formed. If 20,14 is diagonal and 10 is one side, then 10 + 7 = 17 > 10 can be formed and two (2) if 7,15 is adjacent and 20 is diagonal, then 15 + 7 = 22 "20 can be formed. If 7,20 is adjacent and 15 is diagonal, then 20 + 7 = 27" 15 can be formed

A = 5, B = 7, C = 4, two line segments are sides and the other line segment is diagonal. Q: how many parallelograms with different shapes can be drawn

There is only one
The sum of any two sides of the triangle is greater than the third side