In the diamond ABCD with side length of 1, ∠ bad = 60 ° and E is the midpoint of BC, then the vector AE is multiplied by the vector AC

In the diamond ABCD with side length of 1, ∠ bad = 60 ° and E is the midpoint of BC, then the vector AE is multiplied by the vector AC

AE*AC=(AB+1/2BC)(AB+BC)
=(AB+1/2AD)(AB+AD)=AB^2+3/2AB*AD+1/2AD^2=1+3/2*1*1*cos60°+1/2=9/4

Given that the side length of square ABCD is 1, let AB = a, BC = B, then what is the module of A-B?

Because vector BC = vector ad, in fact, the vector of A-B is ab-ad = dB, the module of vector DB is the triangle, and the oblique side length of abd is the root 2,

If the side length of square ABCD is 1, vector AB = a, vector BC = B and vector AC = C, then / A + B + C / =?
ji qiu

Vector a + vector B + vector C = vector AC + vector C = 2 times vector C
The length of vector C is the length of the diagonal of a square: root 2,
So two times the length of vector C is two times the root 2,
Namely
/A + B + C / = 2 times root 2

In rectangle ABCD, let vector AB = vector a, vector ad = vector B, vector AC = vector C
In rectangle ABCD, let vector AB = vector a, vector ad = vector B, vector AC = vector C, and the absolute value of vector a = 2, then the absolute value (vector a-vector B + vector C) is obtained=_____

4 vector C = vector AC = vector AB + vector BC, so vector a-vector B + vector C = ab-ad + AB + BC, and vector ad = vector BC, namely vector a-vector B + vector C = ab-ad + AB + BC = 2Ab = 2A = 4