The function y = - 2x ^ 2-4x + 3 is known. When the independent variable x is in the following value range, calculate the maximum or minimum value of the function respectively, and calculate the value of the function And find the value of the corresponding independent variable x when the function takes the maximum or minimum value

The function y = - 2x ^ 2-4x + 3 is known. When the independent variable x is in the following value range, calculate the maximum or minimum value of the function respectively, and calculate the value of the function And find the value of the corresponding independent variable x when the function takes the maximum or minimum value

Y = - 2 (x + 1) ^ 2 + 5, we can see that the function y is a function with x = - 1 as the axis of symmetry. By marking the value range of X on the image of function y, we can get the maximum and minimum value of function y corresponding to the value of X,

Given the function y = x & # 178;, find the maximum and minimum value when - 2 ≤ x ≤ a, and find the value of the corresponding independent variable x

When x is greater than or equal to - 2 and less than or equal to 0,
The maximum is f (- 2) = 4
The minimum value is f (a) = a ^ 2
When x is greater than 0 and less than 2
Maximum f (- 2) = 4
Minimum f (0) = 0
When x is greater than or equal to 2
Maximum f (a) = a ^ 2
Minimum f (0) = 0

Given the inverse scale function y = - 3 / 2x, the value range of the independent variable X of this function is____________________ How to ask

If there are no other restrictions, the value range of X is (- infinity, 0) U (0, + infinity), in fact, it cannot take 0

In the function y = 1 / 2x + 1, when - 1 is less than or equal to y and less than or equal to 2, the corresponding value range of X
Such as the title, urgent! Process

Let 2x + 1 = t
Then y = 1 / T
Inverse scale function image
Let y = - 1 and 2
Find the corresponding value of T (note that t is not equal to 0)
2x+1=t
Find the range of X