Let - 5 belong to the set {xix2-ax-5 = 0}, then the sum of all elements in the set {x2-4x-a = 0} is? "

Let - 5 belong to the set {xix2-ax-5 = 0}, then the sum of all elements in the set {x2-4x-a = 0} is? "

According to the first condition, a = - 4
So the set {x2-4x-a = 0} is {x2-4x + 4 = 0}, all elements are 2, - 2, and the sum is 0

Given - 5 ∈ {x | x2-ax-5 = 0}, find the sum of all elements in the set {x | x2 = ax = 3 = 0}
x|x2+ax+3=0

Can the equation x2 = ax = 3 = 0 hold?

Given the set a = {x | x2 + 4x = 0}, B = {x | x2 + ax + a = 0}, if B is contained in a, finding a satisfies the condition

A = {x | x ^ 2 + 4x = 0} = {- 4,0} B = {x | x ^ 2 + ax + a = 0} if B is contained in a, then B = empty set or B = {- 4} or B = {0} or B = {- 4,0} ① B = empty set Δ = a ^ 2-4a ＜ 0, so 0 ＜ a ＜ 4 ② B = {- 4} has (- 4) + - 4) = - A, (- 4) * - 4) = a has no solution ③ B = {0} has 0 + 0 = - A, 0 * 0 = AA = 0 ④ B = {- 4,0

Given that - 5 belongs to {X / x square - AX-5 = 0}, then the sum of all elements in the set {X / x square - 4x-a = 0} is?

Answer 2