Let a = {x │ X2 - (a + 2) x + 2A

Let a = {x │ X2 - (a + 2) x + 2A


x^2-(a+2)x+2a



Set a = (x belongs to R / x2 + 4x = 0) set B is a set composed of the roots of equation x2 + 2 (a + 1) x + A2-1 = 0, B is a subset of a, find the value range of real number a


A={0,-4},
When B = (?) 216;, we can get △ = 8 (a + 1)

Elden Ring Premiere

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