2A ^ 2b-5b ^ 3-A ^ 3B ^ 2 + A ^ 4. (1) arrange by the descending power of A. (2) arrange by the ascending power of B

2A ^ 2b-5b ^ 3-A ^ 3B ^ 2 + A ^ 4. (1) arrange by the descending power of A. (2) arrange by the ascending power of B

(1) according to the descending power of a: A ^ 4-A & # 179; B + 2A & # 178; b-5b & # 179;;
(2) according to the ascending power of B: A ^ 4 + 2A & # 178; B-A & # 179; B & # 178; - 5B & # 179

Please use the rectangle to design a plane figure and explain the rule of multiplication of polynomial by monomial, that is, m (a + B + C) = am + BM + cm

The area of a rectangle is equal to length times width
Three rectangles with length a, B, C and width m are connected according to their length direction to form a new rectangle. The area of the new rectangle is the sum of the area of the original three small rectangles

am+bm+cm
Factorization
hard
Help

m(a+b+c)

Write the following polynomials in the form of the product of integers: (1) the quadratic power of X + x = - (2) the quadratic power of X - 1 = - (3) am + BM + cm=——

（1）x(x+1)；（2）(x-1)(x+1)；（3）m(a+b+c)

Given a = 2A ^ 2 + 3ab-2a-1, B = - A ^ 2 + AB-1 and a + B + C = 0, find the polynomial C

From the question, 2A ^ 2 + 3ab-2a-1 + (- A ^ 2 + AB-1) + C = 0
a²+4ab-2a-2+C=0
So C = - A & # 178; - 4AB + 2A + 2

What are the conditions of a > 0 and a < 0 in fraction B,

If a / b > 0 or 0, a * b > 0 means that a and B have the same number
When a / b

Given the square of the algebraic formula x (the 5th power of AX + the 3rd power of BX + Cx) / the 4th power of X + the square of DX, when x = 1, the value is 1, find the value when x = - 1?

x=1
(a+b+c)/1+d=1
x=-1
-(a+b+c)/1+d=-1

We know that y = the seventh power of AX + the fifth power of BX + the third power of Cx + DX + e, when x = 2, y = 23; when x = - 2, y = - 35, find E

X = 2Y = the seventh power of AX + the fifth power of BX + the third power of Cx + DX + e = the seventh power of a * 2 + the fifth power of B * 2 + the third power of C * 2 + D * 2 + e = 23, so the seventh power of a * 2 + the fifth power of B * 2 + the third power of C * 2 + D * 2 = 23-ex = - 2Y = the seventh power of AX + the fifth power of BX + the third power of Cx + DX + e = - the seventh power of a * 2 - the fifth power of B * 2 -

Given that the polynomial 3x3 + KX & # 178; + 3x + 1 can be divisible by X & # 178; + 1, and the quotient is 3x + 1, what is k?

(X & # 178; + 1) (3x + 1) = 3x3 + X & # 178; + 3x + 1, so k = 1

Solve the equation in a proper way, 2007x + 2008y = 20072008x + 2007y = 2008

2007x+2008y=2007.1,
2008x+2007y=2008.2
1 + 2
4015x+4015y=4015
x+y=1.3
Substitute formula 3 into Formula 1
2007x+2008y=2007
2007x+2007y+y=2007
2007(x+y)+y=2007
2007+y=2007
y=0
x+0=1
x=1
So x = 1, y = 0