If the result of inequality 1 / 3 (2x-k) > x-k is X There's another one Given that the solutions X and y of the equations y-2x = m (1), 2Y + 3x = m + 1 (2) satisfy 2x + y ≥ 0, the value range of M is obtained.

If the result of inequality 1 / 3 (2x-k) > x-k is X There's another one Given that the solutions X and y of the equations y-2x = m (1), 2Y + 3x = m + 1 (2) satisfy 2x + y ≥ 0, the value range of M is obtained.

If the result of inequality (1 / 3) (2x-k)] > x-k is x3x-3k, X

How to solve the system of inequalities: 2 (x-3) ≤ x + 1 2x-1 / 3-5X + 1 / 2 ≥ 1?

2x-6 ≤ x + 1 x ≤ 7 2x-1 / 3-5X + 1 / 2 ≥ 1 multiply both sides by 6 4x-2-15x + 3 ≥ 6 - 11x + 1 ≥ 6 - 11x ≥ 5 x ≥ - 5 / 11 supplement: 2x-1 / 3-5X + 1 / 2 ≥ 1 now consider whether 2x-1 / 3-5X + 1 / 2 ≥ 1 Li 1 / 3 and 1 / 2 are independent or multiply both sides by 6 12x-2-30x + 3 ≥ 6 - 18x + 1 ≥ 6 - 18x ≥ 5 x ≥ - 5 / 18

If the solution set of inequality system X − a > 2B − 2x > 0 is - 1 < x < 1, then (a + b) 2009=______ ．

From the inequality, we get x > A + 2, x < 12b, ∵ - 1 < x < 1, ∵ a + 2 = - 1, 12b = 1 ∵ a = - 3, B = 2, ∵ (a + b) 2009 = (- 1) 2009 = - 1

Inequalities x + 3 > 0, - 2x

x+3>0
∴x>-3
-2x-7/2
2x+1>=0
∴x>=-1/2
The solution set of inequality system is
x>=-1/2

Can the highest term of a polynomial be the same,
2X plus 1 and X divided by the square of Y minus 1, which is a polynomial
The right person,

(1) The number should be three
(2) 2X + 1 is a polynomial

The solution set of inequality  2x-3 / x + 2  1

Transfer of original inequality
(2x-3)/(x+2) -1>0
Pass score: (X-5) / (x + 2) > 0
The above formula is equivalent to (X-5) (x + 2) > 0
The solution is x > 5 or X5 or X

Several mathematical problems, simplify
3a^b-[2ab-2(a^2b+2ab^2)]
x(-6x-9)-x(-8x-15)+2X(3-X)
7X^3Y^2/[(-7X^5Y^3)/(-1/3X^3Y^2)]

3a^b-[2ab-2(a^2b+2ab^2)]=3a²b-（2ab-2a²b-2ab²)=3a²b-2ab+2a²b+2ab²=5a²b+2ab²-2abx(-6x-9)-x(-8x-15)+2X(3-X)=-6x²-9x+8x²+15x+6x-2x²=12x7X^3Y^2/[(-7X...

Find the solution set of inequality (1 / | 2x-3 |) > 2

(1/|2x-3|)>2
∴0＜|2x-3|＜1/2
∴-1/2＜2x-3＜1/2;
5/2＜2x＜7/2;
5/4＜x＜7/4;
2x-3≠0;
5 / 4 ＜ x ＜ 7 / 4 and X ≠ 3 / 2;
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If X & sup2; + Y & sup2; = 25, xy = 7 and X is greater than y, then X-Y is obtained

It is known that x2 + y2 = 25 and xy = 7
Then (x - y) 2 = x2 + Y2 - 2XY
= 25 - 14 =11
So X-Y = root 11

Solving inequality x + 2 of 2 > (2x-1 of 3) - 2x

2 of X + 2 > (3 of 2x-1) - 2x
3x+6＞4x-2-12x；
11x＞-8;
x＞-8/11;
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