1/x^2+9/(4x^2-4)=1 ,

1/x^2+9/(4x^2-4)=1 ,

1/x^2+9/(4x^2-4)=1
4x^2-4+9x^2=x^2(4x^2-4)
4x^4-17x^2+4=0
(x^2-4)(4x^2-1)=0
therefore
X ^ 2 = 4 or x ^ 2 = 1 / 4
thus
X = ± 2 or x = ± 1 / 2

The solution equation: (1) 2 (X-2) - 3 (4x-1) = 9 (1-x); & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; (2) 1 − 2x3 = 3x + 17-3

(1) If we remove the brackets, we get 2x-4-12x + 3 = 9-9x; if we remove the brackets, we get: - x = 10; if we remove the denominator, we get 7 (1-2x) = 3 (3x + 1) - 63; if we remove the brackets, we get 7-14x = 9x = 3-63; if we remove the brackets, we get - 14x-9x = 3-63-7; if we merge the same category, we get - 23x = - 67; if we change the coefficient to 1, we get x = 6723