4x^n+2-9x^n+6x^n-1-x^n-2 4X ^ (n + 2) - 9x ^ n + 6x ^ (n-1) - x ^ (n-2), n is an integer and greater than 2

4x^n+2-9x^n+6x^n-1-x^n-2 4X ^ (n + 2) - 9x ^ n + 6x ^ (n-1) - x ^ (n-2), n is an integer and greater than 2

4x^(n+2)-9x^n+6x^(n-1)-x^(n-2)
=x^(n-2)*(4x^4-9x^2+6x-1)
=x^(n-2)*[(2x^2)^2-(3x-1)^2]
=x^(n-2)*(2x^2+3x-1)(2x^2-3x+1)
=x^(n-2)*(2x^2+3x-1)(x-1)(2x-1)

（16x-13)/(4x-3)+（40x-43)/(8x-9)=（32x-30)/(8x-7)+（20x-24)/(4x-5)
....

（16x-13)/(4x-3)+（40x-43)/(8x-9)=（32x-30)/(8x-7)+（20x-24)/(4x-5)4-1/（4x-3）+5+2/（8x-9）=4-2/（8x-7)+5+1/(4x-5)2/（8x-9）+2/（8x-7)=1/（4x-3）+1/(4x-5)2(8x-9+8x-7)/[(8x-9)(8x-7)]=(4x-3+4x-5)/[(4x-...

Mathematics problems (16x-13) / (4x-3) + (40x-43) / (8x-9) = (32x-30) / (8x-7) + (20x-24) / (4x-5)
Online, etc··············
Seeking process···············

(4 (4x-3) - 1) / 4x-3 + (5 (8x-9) + 2) / (8x-9) = (4 (8x-7) - 2) / (8x-7) + (5 (4x-5) + 1) / (4x-5) is sorted out to get 2 / (8x-9) - 1 / 4x-3 = 1 / (4x-5) - 1 / (8x-7), and both sides are divided into 1 / (4x-5) (8x-7) = 1 / (8x-9) (4x-3) to simplify (4x-5) (8x-7) = (8