2x²-8=0 （x-2）²-x+2=0 (x-3)²+2x(x-3)=0 (x-2)²=2x-4 (2x-1)²=x²-4 Solving quadratic equation with one variable by factorization

2x²-8=0 （x-2）²-x+2=0 (x-3)²+2x(x-3)=0 (x-2)²=2x-4 (2x-1)²=x²-4 Solving quadratic equation with one variable by factorization

1. 2 (x + 2) (X-2) = 0, x + 2 = 0 or X-2 = 0, X1 = - 2, X2 = 2.2, (X-2) ^ 2 - (X-2) = 0 (X-2) (x-3) = 0x1 = 2, X2 = 3,3, (x-3) ^ 2 + 2x (x-3) =. 0 (x-3) (x-3 + 2x) = 0x-3 = 0 or 3x-3 = 0x1 = 3, X2 = 1,4, (X-2) ^ 2-2 (X-2) = 0 (X-2) (x-4) = 0x1 = 2, X2 = 4.5, 4x ^ 2-4x + 1-x ^ 2 + 4 =

Given that x + y = 1 / 2, xy = - 3 / 8, find the value of (X-Y) &#
Semicolons are written in words. It's about factoring

X + y = 1 / 2
(x + y) ² = x & #178; + Y & #178; + 2XY = 1 / 4
Xy = - 3 / 8
X & # 178; + Y & # 178; = 1 / 4-2xy
(X-Y) ² = x & #178; + Y & #178; - 2XY = 1 / 4-2xy-2xy = 1 / 4-4xy = 1 / 4-4 * (- 3 / 8)
=7 / 4