3 / 4x minus 25% is 12

3 / 4x minus 25% is 12

49/3

3 / 4x equals x minus 0.4 times 6 / 5

The results and detailed process have been thought out in the exercise book

Find the value range of X that makes the formula √ x-3 / √ x ^ 2-x-2 meaningful

Greater than or equal to 0 under root sign
x-3≥0
x≥3
The denominator is not equal to 0
So x & sup2; - X-2 > 0
(x-2)(x+1)>0
x2
So x ≥ 3

1. Given that X: y = 2:3, and 2x + Y / 2-1 = X-Y / 3, find the value of X and Y. 2. Given that the value of X and Y satisfies the equation x + 1 / 2 = y + 3 / 4 = x + Y / 5, find the formula
3x + 2Y + 1 / x + 2Y + 3!

1, X: y = 2:3, then x = 2 / 3y2x + Y / 2-1 = X-Y / 3, namely 2 * 2 / 3Y + Y / 2-1 = 2Y / 3-y / 3, namely 4Y / 3 + Y / 2-1 = Y / 3, namely 4Y / 3 + Y / 2-y / 3 = 1y = 2 / 3, x = 4 / 92, x + 1 / 2 = y + 3 / 4 = x + Y / 5, namely 5 (x + 1) = 2 (x + y) 2 (x + 1) = y + 3, then y = 7, x = 43x + 2Y + 1 / x + 2Y + 3 = 9 / 7

How to transform the two formulas y-4 = 2 (x-3) 2x-y-2 = 0

y-4=2x-6
y-2x-4+6=0
y-2x+2=0
2x-y-2=0

1 / 2x-3 / 2Y = 12 how to use X to express y? How to use y to express x

1/2x-3/2y=12
Double two on both sides
x-3y=24
3y=x-24
y=(x-24)/3
x-3y=24
x=3y+24

1. Decompose the factor 4A & # 178; - 5 in the range of real numbers
Which is bigger than 2, 2 times root 2 minus root 3 or root 8 minus root 5
What is the absolute value of 3,3 - π minus π
4, if (2x-1): x = 3:1, then x is?

1. (2a + radical 5) * (2A - radical 5)
2. In the commercial method, the root 8 minus the root 5 is divided by twice the root 2 minus the root 3, and the result is greater than 1, so the root 8 minus the root 5 is bigger
3. If 3 - π is less than 0, its absolute value is π - 3, then minus π, the result is - 3
4、3x=2x-1,x=-1

Decomposing the factor 4A & # 178; b-8ab & # 178; + 12ab in the real range

Original formula = 4AB (a-2b + 3)

The square of X-1 / the square of x-2x + 1 is meaningful if --. The condition equal to 0 is --

If the square of X-1 / the square of x-2x + 1 is significant, it is (x ≠ 1). If it is equal to 0, it is (x = - 1)
Idea: when denominator ≠ 0, it is meaningful, when numerator = 0 and denominator ≠ 0, the value of fraction is 0

If (x + 2) 0-3 (2x + 1) - 2 is meaningful, then the value range of X is ()
A. X ≠ - 2b. X ≠ − 12C. X ≠ - 2 or X ≠ − 12D. X ≠ - 2 and X ≠ − 12

X + 2 ≠ 02x + 1 ≠ 0, the solution is: X ≠ - 2 and X ≠ - 12