Solve the equations x − 2Y = − 5x + 2Y = 11

Solve the equations x − 2Y = − 5x + 2Y = 11

The system of equations x − 2Y = − 5 (1) x + 2Y = 11 (2) (1) + (2) is obtained, 2x = 6, x = 3, substituting x = 3 into (1) is obtained, y = 4, the solution of the original system of equations is x = 3Y = 4

How to solve the system of equations y-2x = 3 x-2y = 11

y-2x=3 （1）
x-2y=11 （2）
(1) X2: 2y-4x = 6 (3)
(3) If + (2) is - 3x = 17, then x = - 17 / 3
Substituting x = - 17 / 3 into (1) yields y = 2x + 3 = - 2x (- 17 / 3) + 9 / 3 = - 25 / 3
End of solution

Solve the equations 1. X + 1 / 3 = 2Y 2. 2 (x + 1) - y = 11

The results show that 3x-6y = - 1
2x-y=9 ②
① - 9x = - 55 for - 2 * 6
X=55/9
Substituting x = 55 / 9 into (1) yields y = 29 / 9
The solution of the original equations is: x = 55 / 9
Y=29/9

Given that the solution of the equations x + 2Y = 10 ax + by = 1 about X and Y is the same as that of 2x-y = 5 BX + ay = 6, find the value of (a + b) 2005
It is known that the solutions of the equations x + 2Y = 10 ax + by = 1 for X and y are the same as those of 2x-y = 5 BX + ay = 6, and the value of (a + b) 2005 is obtained

x＋2y＝10.(1)
2x－y＝5.(2)
(1) + (2) * 2
5x=20
x=4
Substitute (1) to get
4+2y=10
y=3
Solution
x=4
y=3
be
4a＋3b＝1
4b＋3a＝6
Add it up and you'll get
7a+7b=7
a+b=1
The power of (a + b)
=The power of 1
=1

How to solve the equations of {5x = 2Y (1), 2 (2Y + X + y) = 68 (2)?

5x=2y（1）
2（2y+x+y）=68（2）---->2*2y+2x+2y=68 (3)
Substituting (1) into (3) 2 * 5x + 2x + 5x = 68 17x = 68 x = 4 (4)
Substituting (4) into (1) 5 * 4 = 2Y, y = 10

To solve the system of equations X: y = 2:3 3x + 2Y = 24

y=(3/2)x
2y=3x
6x=24
x=4
y=6

To solve the equations: X: y = 2:3. 3x + 2Y = 24

x:y=2:3
3x+2y=24
X = 2Y / 3 is obtained from the original
Substituting into formula 2, 4Y = 24
So y = 6
So x = 4, y = 6

Solving equations: 3x + 2Y = 24 X: y = 2:3
-Urgent. There are not too many reward points. We will make up for them later

Let x = 2A, y = 3A
3X+2Y=12a=24
a=2
X=4,Y=6

1. Solutions of 2 (x + y) - (X-Y) = 3 (x + y) - 2 (X-Y) = 12, 2x-3y = - 25X + 2Y = 14 equations

1.x=1,y=2/3
2.x=2,y=2

2x-3y = 2 (2x-3y + 5) / 7 + 2Y = 9, is that ok

2x-3y=2 （1）
（2x-3y+5)/7+2y=9 （2）
Substituting (1) into (2)
(2+5)/7+2y=9
2y=9-1=8
therefore
y=4
Substituting (1)
2x-12=2
2x=14
therefore
x=7
y=4