2x-3y-2=0 (2x-3y+5)/7+2y=9 x= y=

2x-3y-2=0 (2x-3y+5)/7+2y=9 x= y=

2x-3y=2
arcsinx-x
7/7+2y=9x
1+2y=9x
That is, 2x-3y = 2
9x-2y=1
The solution is x = 7 / 31
y=-16/31

Given a = 2x-3y, B = x-2y + 1, and X-Y = 2, find the value of a-b

A-B
=（2x-3y）-(x-2y+1)
=2x-3y-x+2y-1
=x-y-1
=2-1
=1

Solution of equation {4x + 3Y = 7 {2x-5y = 5} by addition subtraction elimination method
﹛2x-3y=5

2x-5y=5② ②*2 4x-10y=10
4x+3y=7
The following formula minus the above formula gives 13y = - 3, y = - 3 / 13
Substituting 2, we get x = 25 / 13

Given X / 3 = Y / 4 = Z / 5, then the value of X + Y / x-2y + 3Z is?

x /3=y /4=z /5=k,
x=3k,y=4k,z=5k,
(x+y)/(x-2y+3z)
=(3k+4k)/(3k-8k+15k)
=(7k)/(10k)
=7/10.

Given that 3 / 3 x equals 4 / 4 y equals 5 / 5 Z, find the value of x-2y + 3Z x + y?
emergency

x/3=y/4=z/5
We can get X / 3 = Y / 4 and Y / 4 = Z / 5
If x / 3 = Y / 4 is multiplied by multiple 12, 4x = 3Y can be obtained
So x = 3 / 4Y
In the same way
When y / 4 = Z / 5 is multiplied by the same multiple 20, 5Y = 4Z is obtained
So y = 4 / 5Z
Because x = 3 / 4Y, y = 4 / 5Z
So x = 3 / 5Z
x+y/x-2y=3z=（3/5z+4/5z）/（3/5z-8/5z+3z）
The answer is 7 / 10

10: Y = 4:7 X: z = 3:5 x-2y + 3Z = 30

From X: y = 4:7, X: z = 3:5, x-2y + 3Z = 30, we get x = 4 / 7Y, z = 5 / 3Y, substitute x = 4 / 7Y, z = 5 / 3Y into x-2y + 3Z = 30, get 4 / 7y-2y + 3 × 5 / 3Y = 30, get y = 8.4, substitute y = 8.4 into x = 4 / 7Y, z = 5 / 3Y, get x = 4.8, z = 14

If x + 2y3 = y + 3z4 = Z + 5x5, then x: Y: Z=______ ．

The original equations are reduced to: x + 2y3 = y + 3z4x + 2y3 = Z + 5x5, and the results are: 4x + 5Y = 9z ① 10x − 10Y = 3Z ② ① × 2 + ②: 18x = 21z, x = 76z, ① × 5 - ② × 2: 45y = 39z, y = 1315, X: Y: z = 76z: 1315z: z = 35:26:30, so the answer is: 35:26:30

If x + 2y3 = y + 3z4 = Z + 5x5, then x: Y: Z=______ ．

The original equations are reduced to: x + 2y3 = y + 3z4x + 2y3 = Z + 5x5, and the results are: 4x + 5Y = 9z ① 10x − 10Y = 3Z ② ① × 2 + ②: 18x = 21z, x = 76z, ① × 5 - ② × 2: 45y = 39z, y = 1315, X: Y: z = 76z: 1315z: z = 35:26:30, so the answer is: 35:26:30

Calculate 1 - (x-2y / x + 2Y) / (x ^ 2-y ^ 2 / 4xy-x ^ 2-4y ^ 2)

1-[(x-2y)/(x+2y)] * [(x+y)(x-y)]/-[(x-2y)^2]
=1+(x^2-y^2)/(x^2-4y^2)

Calculate (x + 2Y) (x-2y) (x ^ 2-4y ^ 2) where x = 5 / 3 and y = 2 / 3

(x+2y)(x-2y)(x^2-4y^2)
=(x+2y)(x-2y)(x+2y)(x-2y)
=[(x+2y)(x-2y)]²
x=5/3 y=2/3
x+2y=5/3+4/3=9/3=3
x-2y=5/3-4/3=1/3
(x+2y)(x-2y)=3×1/3=1
arcsinx-x
=1²
=1