Solve the equation 25 (x + 3) &# 178; - 16 (X-2) &# 178; = 0

Solve the equation 25 (x + 3) &# 178; - 16 (X-2) &# 178; = 0

A = {x | x + 1 ＞ 0}, B = {x | X & # 178; - 4 ≤ 0}, then CUA ∩ B=

x+1>0
So a is x > - 1
So CUA = {x | x ≤ - 1}
x²-4≤0
-2≤x≤2
So CUA ∩ B = {x | - 2 ≤ x ≤ - 1}

How to solve ax & # 178; - (A-4) x-4 = 0
How to solve this equation? Help to review the solution of the equation, especially the cross multiplication

From the title,
ax²-[a-4]x-4=0
be
(ax+4)(x-1)=0
If a = 0
Then the solution of the equation is x = 1
If a ≠ 0
Then the solution of the equation is x = 1 or x = - 4 / A

It is known that a = {x | X & # 178; - X-2 > 0}, B = {x | X & # 178; + 3x-4

It is known that a = {x | X & # 178; - X-2 > 0},
A:(x-2)(x+1)＞0;
X ＞ 2 or X ＜ - 1;
B={x|x²+3x-4