The relation between set a = {x | X & # 178; – 4 = 0} and set B = x | x | = 2} is

The relation between set a = {x | X & # 178; – 4 = 0} and set B = x | x | = 2} is

A=B

（x-5)²-2（x-5）=0

The original formula is changed to
(X-5) (X-5-2) = 0 (extract the common factor X-5)
(x-5)(x-7)=0
x1=5
x2=7
Please accept

(X & # 178; + Y & # 178;) &# 178; - 3 (X & # 178; + Y & # 178;) - 4 = 0, find X & # 178; + Y & # 178=_______

4

1. (X & # 178; + Y & # 178;) &# 178; - 4 (X & # 178; + Y & # 178;) - 5 = 0, then x & # 178; + Y & # 178; = ()
2. If X & # 178; - 3xy-4y & # 178; = 0, then x / y = ()
3.3x²+2x=3,

This paper (x (x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\#178; = 5x & #178; - 3xy-4y & #178; = 0 (x-4y) (x + y) = 0  x = 4Y or X