Given Sina + cosa * √ 3 = (2m + 1) / (3-m), find the value range of M

Given Sina + cosa * √ 3 = (2m + 1) / (3-m), find the value range of M

The original formula = 2Sin (a + π / 6) = (2m + 1) / (3-m), that is - 1

If M = (2-sina) / (2 + COSA), then the value range of real number m is
RT

Find points a (2,2) and B (- cosa, Sina), slope range

When k takes what value, the fractional equation 1 / 1-x = x + K / X (x-1) - 3 / X has no solution

Is x + k a molecule or something?
Let's talk about the way of thinking. According to the normal steps, the solution x is expressed by K. if the equation has no solution, it means that the equation has an increasing root, and the increasing root is 0 or 1
Just let x = 0 or 1 find the corresponding K

If the fractional equation x-a / X-1 - 3 / x = 1 has no solution, the value of a is obtained
I think as long as the value of X is equal to 1 or 0, it has nothing to do with A. does a fractional equation have an increasing root but no root?

If x (x-1) x (x-a) - 3 (x-1) = x (x-1) x & # 178; - ax-3x + 3 = x & # 178; - x (a + 2) x = 3 if a = - 2, the equation has no solution if a ≠ - 2x = 3 / (a + 2) if x is an increasing root, then there is no solution increasing root, that is, the common denominator is 0 x (x-1) = 0, x = 13 / (a + 2) = 0, 3 / (a + 2) = 1A + 2 = 3A = 1, so a = - 2, a = 1