Solving the system of inequalities 5x + 5 (10-x) ≤ 44 x + 2 (10-x) > 14

Solving the system of inequalities 5x + 5 (10-x) ≤ 44 x + 2 (10-x) > 14

First solve the left, then the right, and then the intersection

Write the inequality | 1-3x|
The first inequality | 1-3x|

|1-3X|

1. If the solution set of inequality-x ^ 2-5x + 14 < 0 is 2, a = {1,2}, B = {3, a}, and a ∩ B = {1}, then a ∪ B=
3. If f (2x-3) = x + 1, X ∈ (1,2], then f (1-x)

Question 1: the first step is to simplify: - x ^ 2-5x + 14 = - (x ^ 2 + 5x-14) = - (x + 7) (X-2);
The second step is to calculate: - x ^ 2-5x + 14 ＜ 0, that is - (x + 7) (X-2) ＜ 0, so (x + 7) (X-2) > 0, that is, the two have the same sign. When both are greater than zero, the answer is x > 2. When both are less than zero, the answer is x2 or X

Given that the solution set of the inequality 5x + a greater than 3 about X is x less than 2, find the value of A

5x + a > 3, x > 3-A / 5, and x < 2, that is (3-A) / 5 < 2,
A＞-7