If the minimum value of quadratic function y = x ^ 2 + 4x + A is 2, then the value of a is 2__

If the minimum value of quadratic function y = x ^ 2 + 4x + A is 2, then the value of a is 2__

y=x^2+4x+a=(x+2)^2+(a-4)
Obviously, when x = - 2, y has the minimum value (A-4), so A-4 = 2, that is, a = 6

When the minimum value of quadratic function y = x2-2x + m is 5, M=______ ．

From the minimum value of quadratic function y = x2-2x + m is 5, 4ac − b24a = 4m − 44 = 5, M = 6

Given the quadratic function y = x2 + 2x-1, the minimum value of the quadratic function is many

y=x²+2x-1
y=x²+2x+1-2
y=（x+1）²-2
A = 1 ＞ 0, y has a minimum value
When x = - 1, y has a minimum value of - 2

Given that the quadratic function y = a (x-1) * 2 + B has a minimum value of - 1, then the relationship between a and B

The quadratic function y = a (x-1) * 2 + B has the minimum value - 1
Therefore, if the opening of the function is upward, a must be greater than 0, and the minimum value is - 1, so B = - 1
Therefore, a > 0 > - 1
So a > b