If M satisfies the relation √ 3x + 5y-2-m + √ 2x + 3y-m = √ x-1999 + y times √ - X-Y + 1999, try to find the value of M

If M satisfies the relation √ 3x + 5y-2-m + √ 2x + 3y-m = √ x-1999 + y times √ - X-Y + 1999, try to find the value of M

Solutions x-1999 + y ≥ 0 and - X-Y + 1999 ≥ 0
So x-1999 + y = 0
So √ 3x + 5y-2-m + √ 2x + 3y-m = 0
That is, 3x + 5y-2-m = 0, 2x + 3y-m = 0
The solution of three equations is m = 2001
Xiaobai, do you understand?

[(2x ^ 2 + y) ^ 2-5y ^ 2 (3x ^ 2 + 1) - 4 (x ^ 2 + y) (x ^ - y)] / 5x ^ y, where x = 99, y = 2 / 15

Original formula = [4x ^ 4 + y ^ 2 + 4x ^ 2y-15y ^ 2x ^ 2-5y ^ 2-4x ^ 4 + 4Y ^ 2] / 5x ^ 2Y
=[4x^2y-15y^2x^2]/5x^2y
=4/5-3y
Generation value
simple form
=4/5-3*2/15
=4/5-2/5
=2/5

Given equation 2x-4x + 6x-8x + 10x-12x + －2000x =－y+3y－5y+…… +From 1999y to 2008, then x + y=

=008 because 2x-4x + 6x-8x + 10x-12x +... - 2000x = 0y + 3y-5y +... + 1999y-2008
-1000x=1000y-2008
1000x+1000y=2008
x+y=2.008

Addition subtraction elimination method for solving bivariate linear equation: 7x-4y = 4,5x-4y = - 4
The content should be complete

Formula 1 minus formula 2
2x=8
X = 4 (formula 1)
Take Formula 1 into the formula
y=6