The discontinuous point of function f (x) = {X-1, x0, is (), and its type is (). What to fill in

The discontinuous point of function f (x) = {X-1, x0, is (), and its type is (). What to fill in

The discontinuity of function f (x) = {X-1, x0} is (x = 0), and its type is (jump discontinuity in the first kind of discontinuity)

Finding the removable discontinuity of function y = X-2 / x ^ 2-x-2
Thank you

Your topic should be
Y = (X-2) / (x ^ 2-x-2). Otherwise, according to your writing, only the middle 2 / x ^ 2 has a breakpoint
Y = (X-2) / ((X-2) (x + 1)),
When x ≠ 2, y = 1 / (x + 1)
When x = 2, it is meaningless. Then the discontinuity point can be removed, that is, x = 2, y = 1 / 3, (2,1 / 3)

The discontinuous point of function y = 1 / (x ^ 2-2x + 1) is
The discontinuous point of function y = 1 / (x ^ 2-2x + 1) is

Y=1/ (x^2-2x+1) = 1/(x-1)^2
Break point: x = 1

X = - 1 is the breakpoint of function y = X-2 / x + 1

The first type of breakpoint, because there is no definition at that point

Simple calculation and writing process 111111 × 99999

111111×999999
=111111*(1000000-1)
=111111000000-111111
=111110888889
You can multiply 999999 into an integer. It's much easier

111111×999999=______ ．

111111 × 99999, = 111111 × (1000000-1), = 1000000 × 111111-111111, = 1111111000000-111111, = 111110888889

Ingenious calculation: 111111 * 222222 / 333333

111111*222222\333333=111111*111111*2/(111111*3)=111111*2/3=222222/3

999999 * 7 + 111111 * 37 = simple

999999*7+111111*37
=111111*9*7+111111*37
=111111*（63+37）
=111111*100
=11111100

Calculation: 111111 × 999999 + 9999 × 7777=______ ．

111111 × 999999 + 999999 × 777777, = (11111 + 777777) × 999999, = 888888888 × (1000000-1) = 888888888 × 1000000-888888, = 888888000000-888888888, = 888887111112

111111×999999=______ ．

111111 × 99999, = 111111 × (1000000-1), = 1000000 × 111111-111111, = 1111111000000-111111, = 111110888889