In the plane rectangular coordinate system, the point a (x, 2) is translated up three unit lengths, and then to the right two unit lengths to get the point B (- 3, y), then x =, y=

In the plane rectangular coordinate system, the point a (x, 2) is translated up three unit lengths, and then to the right two unit lengths to get the point B (- 3, y), then x =, y=

According to the meaning of the title:
2+3=y,x-2=-3
The solution is: x = - 1, y = 5

In the plane rectangular coordinate system xoy, the straight line y = - x rotates 90 ° clockwise around the point O to obtain the straight line L, and the straight line L passes through the point a (a, 3), then
a=

A:
The line y = - x rotates 90 ° clockwise around the origin o to get the line y = X
Point a (a, 3) is on the line y = X
So: a = 3

As shown in the figure, in the plane rectangular coordinate system, ob is on the positive half axis of X, ABO = 90 ° and the coordinates of point a are (1,2). Rotate △ AOB 90 ° clockwise around point a,
Then the above said: the corresponding point C of point O just falls on the hyperbola y = x / R

In the plane rectangular coordinate system, ob is on the positive half axis of X, ABO = 90 ° and the coordinates of point a are (1,2),
Then the coordinates of point B are B (1,2)
After rotating △ AOB 90 ° clockwise around point a, let B and O correspond to D and C respectively,
Then the coordinates of point D are (- 1,2), and the coordinates of point C are (- 1,3)
Then (- 1,3) on hyperbola y = R / x, 3 = R / (- 1), r = - 3

Given the position of the right triangle ABC in the right angle coordinate system as shown in the figure, please write the names of all right triangles which are congruent with the right triangle ABC and have a common edge
Coordinates of the third vertex

I can't see your figure, but I think this problem is mainly about the symmetry of two points with respect to a line. There are three right triangles which are congruent with the right triangle ABC and have a common edge. They share a common edge with AB, and the third point must be the symmetry point of point C with respect to ab. therefore, knowing the coordinates of three points of ABC, we can write out the linear equation of the three sides, Then the coordinates of the two symmetrical points can be obtained by using the property that the slope of the linear equation of the two symmetrical points is perpendicular to it