Using image method to find the approximate solution of the quadratic equation of one variable - X & sup2; + 2x-3 = - 8 (accurate to 0.1)

Using image method to find the approximate solution of the quadratic equation of one variable - X & sup2; + 2x-3 = - 8 (accurate to 0.1)

x1=-1.4;
x2=-0.8
Draw the curve, the symmetry axis is - 1, both sides are symmetrical, take - 2 and 0, and then the solution can be obtained by piecewise approximation

How much is 4 out of 13 divided by 0.75

75 = 3 / 4 divided by a number is equal to the reciprocal of this number, the reciprocal of 3 / 4 is 4 / 3, so the formula is: 4 / 13 divided by 3 / 4 = 4 / 13 multiplied by 4 / 3 = 16 / 39

Solving the equation with the method of Collocation: x square plus 12x minus 15 equals zero

x^2+12x-15=0
x^2+12x=15
x^2+2*6*x+6^2=15+6^2
(x+6)^2=51
So x + 6 = ± √ 51
So x = - 6 ± √ 51

If the equation (M + 3) XM2 − 7 + (m-5) x + 5 = 0 about X is a quadratic equation with one variable, try to find the value of M and calculate the sum of the coefficients of this equation

The original equation can be reduced to 6x2-2x + 5 = 0, so the coefficient of quadratic term is 6, the coefficient of primary term is - 2, the constant term is 5, so the sum of the coefficients is 6 + (- 2) + 5 = 9