(x^2+5x+4)(x^2+5x)+6(x^2+5x)+24

(x^2+5x+4)(x^2+5x)+6(x^2+5x)+24

(x^2+5x+4)(x^2+5x)+6(x^2+5x)+24
=(x^2+5x)(x^2+5x)+4(x^2+5x)+6(x^2+5x)+24
=(x^2+5x)(x^2+5x)+10(x^2+5x)+24
=(x^2+5x+6)(x^2+5x+4)
=（x+2）（x+3）（x+4）（x+1）

When - 3 ＜ x ＜ 5, simplify the square of √ x + 6x + 9 and the square of √ X - 10x + 25=______

X-8 | 8, - 8 | x | 8, square of √ x + 8x + 9 - square of √ X - 81x + 88 = x + 8-8 + x = 8x + 8

How to calculate x square + 10x + 9 = 0?
Isn't it rootless to move the nine?

(X+9)(X+1)=0 X=-9 orX=-1

The second power of X + 10x + 20 = 0 to find x
How long does it take for the car to go up the slope with initial speed V0 = 20m / s, acceleration a = - 4m / S ^, and slope length L = 40m?

X ^ 2 + 10x + 20 = 0 x ^ 2 + 10x + 25-25 + 20 = 0 (x + 5) ^ 2-5 = 0 (x + 5 - √ 5) (x + 5 + √ 5) = 0x = - 5 + √ 5 or x = - 5 - √ 5 2As = (vt) ^ 2 - (V0) ^ 22 * (- 4) * 40 = (VT) ^ 2-20 ^ 2 (VT) ^ 2 = 400-320 (VT) ^ 2 = 80vt = 4 √ 5T = (vt-v0) / a = (4 √ 5-20) / (- 4) = - (√ 5-5) = 5 - √ 5