Substitute the whole into the square of known x-5x = 6 to find the value of square of 10x-2x + 5

Substitute the whole into the square of known x-5x = 6 to find the value of square of 10x-2x + 5

Because: x ^ 2 - 5x = 6
So: 10x - 2x ^ 2 + 5 = - 2 (x ^ 2 - 5x) + 5
= - 2 × 6 + 5
= - 12 +5　＝　－7

Given (2x-a) (5x + 2) = 10x2-6x + B, then a=______ b=______ ．

∵ (2x-a) (5x + 2) = 10x2 + (4-5a) x-2a = 10x2-6x + B, ∵ 4-5a = - 6, B = - 2A, the solution is: a = 2, B = - 4

Given (2x-a) (5x + 2) = 10x2-6x + B, then a=______ b=______ ．

∵ (2x-a) (5x + 2) = 10x2 + (4-5a) x-2a = 10x2-6x + B, ∵ 4-5a = - 6, B = - 2A, the solution is: a = 2, B = - 4

(2x-a) (5x + 2) = the square of 10x-6x-b, then the B power of a =?

（2x-a）（5x+2）=10x²-6x-b
10x²+4x-5ax-2a=10x²-6x-b
（4-5a）x-2a=-6x-b
So: 4-5a = - 6, 2A = B
So: a = 2, B = 4
So a ^ B = 2 ^ 4 = 16