Given the complete set u = {x | x ≤ 4 and X ∈ n +}, a = {x | X & # 178; + ax + 2 = 0, X ∈ u}, find CUA For example, find the complement of A

Given the complete set u = {x | x ≤ 4 and X ∈ n +}, a = {x | X & # 178; + ax + 2 = 0, X ∈ u}, find CUA For example, find the complement of A

First of all, we know that x = 1234, and in set a, because
X ∈ u, so the equation must have a solution, so △ = the square of a - 8 ≥ 0, the solution a is greater than or equal to 2 times the root sign 2
If u increases a in turn, then x is always less than 0, then a ∈ empty set is obtained
CUA = 1234 I don't know if it's right, but it's wrong. Don't spray it. After all, I've forgotten it for several years

Let a = {Y / y = x & # 178; - 2x + 3, X ∈ r}, B = {Y / y = - X & # 178; + 2x + 10, X ∈ r}, find a ∩ B
Let a = {(x, y) / y = x + 1, X ∈ r}, B = {(x, y) / y = - X & # 178; + 2x + 3 / 4, X ∈ r}, find a ∩ B

For set a
The letter of set a is y, which is the requirement of Y
Is [2, + ∞]
For set B
The representative letter of set B is y, which is the requirement of Y
Is [- ∞, 11]
So a ∩ B = [2,11]

Given a = {x | x | ≤ 1, X ∈ r}, B = {y | y = 2x & # 178;}, then a ∩ B=

Set a = {x | x | ≤ 1, X ∈ r} = {x | - 1

When x = - 2, the square of quadratic trinomial equation 2x + MX + 4 = 18, then when x equals 2, the equation is equal to

Substitute x = - 2 into the square of 2x + MX + 4 to get x = - 2
8-2m+4=18
m=-3
When x = 2
Square of 2x + MX + 4
=8+2m+4
=6