Given the set a = {X / X & # 178; + 4x = 0, X ∈ r} B = {X / X & # 178; + 2 (a + 1) x + A & # 178; - 1 = 0, a ∈ R, X ∈ r}, if B & # 8838; a, find the value of real number a

Given the set a = {X / X & # 178; + 4x = 0, X ∈ r} B = {X / X & # 178; + 2 (a + 1) x + A & # 178; - 1 = 0, a ∈ R, X ∈ r}, if B & # 8838; a, find the value of real number a

Because x ^ 2 + 4x = 0
So x = 0 or x = - 4
Set a is {0, - 4}
If B &; a
Then there may be four cases of B, that is, B is an empty set, B = {0}, B = {- 4}, B = {0, - 4}
——————————————————————————————
(1) If B is empty
So 4 (a + 1) ^ 2-4a ^ 2 + 4

The sum of all elements of the set {x | X & # 178; + 4x + 4 = 0} is

(x+2)²=0;
x1=x2=-2;
All elements and = - 2;
Hello, I'm glad to answer for you. Skyhunter 002 will answer your questions
If you don't understand this question, you can ask. If you are satisfied, remember to adopt it
If you have any other questions, please take this question and send it to me. Please understand
I wish you progress in your study