6 ≥ | X-Y | how to use absolute value sign?

6 ≥ | X-Y | how to use absolute value sign?

x-y>=-6,x-y

1. We know that the parabola y = ax & # - 178 passes through a (- 3, - 18), when x=____ The function has the most___ Value, yes___ ; when___ Y decreases with the increase of X
2. The vertex coordinates of parabola y = - 3x & # 178; + 6 are____ When x=____ Y is the most important____ Value, most____ The value is_____ .
3. If the image of the parabola y = - 3x & # is shifted one unit to the left, the analytic expression of the evaluated parabola is____ .
4. Known function y = 1 / (2x & # 178;) - 2
(1) The graph of the function is drawn;
(2) Let the vertex of the function image be p, and the two intersection points of the function image and the X axis be a and B, respectively

1. We know that the parabola y = ax & # - 178 passes through a (- 3, - 18), when x=__ 0__ The function has the most__ Big_ Value, yes_ 0__ ; when__ >0_ 2. The vertex coordinates of the parabola y = - 3x & # 178; + 6 are_ (0,6)___ When x=__ 0__ Y is the most important_ Big___ Value, most_ Big___ The value is_ 6____ 3. Parabola y = - 3

It is known that the square of the parabola y = ax passes through the point (- 1,2). Find the analytic function of the parabola and judge that the point (1,2) is

We can find a = 2, so the square of y = 2x, (1,2) is on the parabola

If the plane region represented by the inequality system X-Y ≥ 0, 2x + y ≤ 2, y ≥ 0, x + y ≤ A is a triangle and its interior, what is the value range of real number a

First, draw the area represented by X-Y ≥ 0, 2x + y ≤ 2, y ≥ 0 in the coordinate system, and then draw x + y ≤ a
You'll find that if you want a triangle in the region,
Let X-Y = 0 and 2x + y = 2 intersect with a, 2x + y = 2 intersect with X axis with B
Then a (2 / 3,2 / 3) B (1,0)
These two points and (0,0) are critical points. If x + y ≤ A is brought in, we can know that,
0 ＜ a ≤ 1 or a ≥ 3 / 4
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