The watt hour meter is marked with "3000r / kWh". If only one consumer works in the circuit of the meter, the dial of the watt hour meter will turn 30R in 6 minutes Then, the electric energy consumed by the appliance is ［ J, and the current passing through it is ］ a

3000r / kWh, that is, 3000r / kWh is 1kwh, then 30R / kWh is 0.01kwh, changing the degree to coke is 0.01 * 1000 * 3600 = 36000 coke
The power is 36000 / 360W = 100W
From the dial, the voltage is 220 v
The current is 100 / 220 = 10 / 22a

A certain electric energy meter is marked with the words of 220V 3W. How many 60W light bulbs can this meter supply at most under the voltage of 220V?

The process is as follows:
According to the parameter "220 V 3A", the output voltage of the meter is u = 220 v
According to the formula of power P = IU, the maximum power of the meter is:
P = IU = 3x220 = 660w, so the number of 60W bulbs allowed is 660 / 60 = 11

The electric energy meter of Xiao Han's family is marked with the words "220 V, 5A". This electric energy meter can make several 220 V and 60 W light bulbs shine normally at the same time

18. First calculate the total electric power that can bear, 220 times 5 equals 1100W, 1100W divided by 60W equals 18

The energy meter of Xiaohua household appliances shows that at the end of April and at the end of May, the energy consumption of Xiaohua household appliances in May is KW · h, electricity charge payable Yuan (calculated according to the average price of 0.5 yuan per kilowatt hour)

Xiaohua's electricity consumption in May is 2178.2kw · h-2138.2kw · H = 40kW · h, and the electricity charge payable is 40kW · h × 0.5 yuan / kW · H = 20 yuan

The watt hour meter is marked with "3000r / kWh". If only one consumer works in the circuit of the meter, the dial of the watt hour meter will turn 30R in 6 minutes Then, the electric energy consumed by the appliance is ［ J, and the current passing through it is ］ a