Three companies share a total electricity meter, and they pay 123.50 yuan in October. How much should each company pay? Li family: number of ammeters 62 Wang family: number of ammeters 58 Liu family: number of ammeters 70

Three companies share a total electricity meter, and they pay 123.50 yuan in October. How much should each company pay? Li family: number of ammeters 62 Wang family: number of ammeters 58 Liu family: number of ammeters 70

Memories take away everything: Hello
The sum of the three sub tables is: 62 + 58 + 70 = 190
Payable by Li family: 123.50 yuan × 62 / 190 = 40.3 yuan
Wang family: 123.50 yuan × 58 / 190 = 37.7 yuan
Payable by Liu family: 123.50 yuan × 70 / 190 = 45.5 yuan
40.3 yuan + 37.7 yuan + 45.5 yuan = 123.5 yuan
Good luck and goodbye

Xiaoming's electricity meter is 186kw this month. He paid 30.8 yuan for electricity and 5.6 kilowatts per kilowatt. How to calculate the electricity meter's power last month

Let the degree of last month be x, and solve the equation (186-x) * 5.6 = 30.8. X = 180.5 should be 0.56 degree. How can there be electricity of 5 yuan and 6 jiao degree