As the circuit shown in the figure, the reading of ammeter A is 0.5A, the reading of ammeter a 'is 0.3A, and the reading of voltmeter V is 6V. What are the resistances R1 and R2 in the circuit?

As the circuit shown in the figure, the reading of ammeter A is 0.5A, the reading of ammeter a 'is 0.3A, and the reading of voltmeter V is 6V. What are the resistances R1 and R2 in the circuit?

According to the circuit diagram, if two resistors are connected in parallel, ammeter a measures the main current, ammeter a 'measures the current of R1 branch, and voltmeter measures the voltage of power supply, then the voltage of power supply is u = 6V, the main current is I = 0.5A, and the current through R1 is I1 = 0.3A

How to see the current of 5A ammeter for 2000 / 5 transformer

If the primary side is 2000a, the secondary side is 5A. The ratio is 2000 / 5 = 400 times. It's easier to convert by connecting 5A ammeter. If the reading of ammeter is directly multiplied by 400 times, it's the current value of the primary side

How does the 300:5a transformer read on the ammeter?

This shall be a watt hour meter with a 300 to 5A current transformer ratio of:
300 / 5 = 60 (Times)
The actual kilowatt hour is obtained by multiplying the kilowatt hour meter by the multiplying factor

Use three single-phase watt hour meters to measure three-phase electricity charges. The watt hour meter is 5 (10) a and the transformer is 100:5. How to calculate the electricity consumption?

The row counting code (stop code minus minimum) of three single-phase watt hour meters multiplied by CT transformation ratio 100 / 5 = 20
For example, a phase 100-80 = 20, B phase 102-81 = 21, C phase 120-95 = 25 (20 + 21 + 25) * 20 = 66 * 20 = 1320
Then the electricity price of 1320 kW. H in current month (period) is equal to the electricity fee payable in current month (period)