How much power can a single-phase meter of 10 (60) a withstand

How much power can a single-phase meter of 10 (60) a withstand

Direct use: 10A current, P = 220 * 10 = 2200W
Use transformer: 60A current. P '= 220 * 60 = 13200w
Physical wolves

Three phase power calculation formula

There are three kinds of power: active power P, reactive power Q and apparent power S. the cosine of phase difference (Φ) between voltage and current is called power factor, which is expressed by cos Φ. In numerical value, power factor is the ratio of active power and apparent power, that is, cos Φ = P / s. three kinds of power and power factor cos Φ is a right angle power

On the calculation of three-phase AC power!
If the power supply voltage is AC three-phase, the voltage of each phase is 220 v,
It is known that the rated voltage of the motor is 380V and the rated current is 15A
1. When the three-phase asynchronous motor starts in star, is the electric power calculation formula: root 3 * u * I * power factor, u is 380V or 220V?
2. When the three-phase asynchronous motor is in angular operation, is the electric power calculation formula: root 3 * u * I * power factor, u is 380V or 220V?

1》 The power supply voltage is AC three-phase electricity, the voltage of each phase is 220 V, the rated voltage of the motor is 380 V, the rated current is 15 A (should be 15 kW △ connected), the motor can be changed to y to adapt to three-phase 220 V operation, the calculation formula u = 220 V, the voltage is low, the current is large, the power remains unchanged

Three phase power calculation formula question?
P = 1.732 × u line × I line × cos Φ 1.732 = don't know the meaning
U line = line voltage 380
I line = line current
Cos Φ = power factor
What does the 1.732 or root sign 3 mean in this formula? Does it represent the total RMS current of three wires per second, or what does it represent?
My personal understanding is that the sum of the total effective currents of the three wires connected by triangle = (line current × 1.732)
Because the current difference between AC and three-phase AC is 120 degrees, the total current of the three wires is not as direct as the phase current multiplied by 3, and the total effective value of the three wires is 1.732 times of the line current
So I think the meaning of the formula is (1.732 × line current) × line voltage
Total power P = total current × voltage U
There are three lines of current sum equal to 0, can't understand, in the case of load work, the sum of energy is 0, physics is wrong

Although your conclusion is correct, the derivation process is completely conjectured, and the total current of three wires is a conjectured and incorrect value. In fact, the sum of three-phase currents with a difference of 120 ° is 0. Therefore, in the case of three-phase balance, the neutral current (the total return current of three phases is the sum of three-phase currents) is 0
The key of this problem is that the three-phase power is equal to the sum of three single-phase power. Let the total power be p total, the power of a phase be PA, the power of B phase be Pb, and the power of C phase be PC. then according to the definition of work, the total work is the sum of three-phase work in the same time. Then p total is equal to PA + Pb + PC = 3PA (when three-phase is balanced). Then calculate PA
For triangle connection, u line = √ 3U phase, I line = I phase. PA = u phase × I phase × cos φ = (1 / √ 3) U line I line cos φ, P total = 3PA = √ 3U line I line cos φ
In the case of star connection, u line = u phase, I line = √ 3I phase. PA = u phase × I phase × cos φ = (1 / √ 3) U line I line cos φ, P total = 3PA = √ 3U line I line cos φ
So no matter star connection or triangle connection, under the condition of three-phase balance, there is always P = 3PA = √ 3U line I line cos φ