A 100W bulb and a 15W bulb are connected in series in a voltage of 220V (rated voltage). Which bulb is on and why

A 100W bulb and a 15W bulb are connected in series in a voltage of 220V (rated voltage). Which bulb is on and why

In a series circuit, the current flowing through the appliance is the same. According to P = I ^ 2 * r, because the resistance of 15W is larger, the power it emits is also larger, so it is brighter than 100W

Two bulbs 100W and 15W are connected in series in the 220 V circuit. What is the actual power consumption of each lamp?
What's wrong with this!

P=U^2/R
Then r = u ^ 2 / P, where u is 220 v
The resistance R1 = 484 and R2 = 3226.7 of the two bulbs are calculated respectively
I = u / (R1 + R2) and I = 0.059
Then p = I ^ 2 * r is used to get the actual power
The solution is P1 = 1.7w, P2 = 11.34w
By calculating the power, we can see that the actual power is lower than the rated power, and the light is not on