A lamp is marked with 220V 100W, B lamp is marked with 110V 100W, when they light up in their respective circuits, why do they consume the same amount of electric energy at the same time

A lamp is marked with 220V 100W, B lamp is marked with 110V 100W, when they light up in their respective circuits, why do they consume the same amount of electric energy at the same time

Because according to w = Pt, w a = P amount × t = 100W × T, W B = P amount × t = 100W × T. because the time is the same, w a = w B. is that understandable?

A lamp is "220V 100W", B lamp is "110V 100W", when they normally light up, the power consumption is ()
A. A lamp more B. B lamp more C. as much D. not sure

According to the formula w = Pt, only the rated power is known, but the working time is not known, so the consumed electric energy cannot be calculated

The L1 220 V 100 W and L2 220 V 10 W are connected in series in a circuit with a voltage of 110 v
What is the actual power of L1 L2 when L1 220V 100W and L2 220V 10W (1) are connected in series in a 110V circuit?
(2) What is the actual power of L1 and L2 in the circuit of 110V in parallel?

The resistance of bulb L1 is: R1 = u ^ 2 / P = 220x220 / 100 = 484 Ω
The resistance of bulb L1 is: R2 = u ^ 2 / P = 220x220 / 10 = 4840 Ω
The total resistance after series connection is: rtotal = R1 + R2 = 484 + 4840 = 5324 Ω
The total current of the circuit is: I = u / R, total = 110 / 5324 = 0.02 a
Because it is in series, the current through each bulb is 0.02 a
Therefore, the power consumed by bubble L1 is:
P1 = I ^ 2r1 total = 0.02x0.02x484 = 0.1936w
The power consumption of bubble L2 is as follows:
P2 = I ^ 2r2 total = 0.02x0.02x4840 = 1.936w
Put them together at 110V,
The power consumption of light bulb L1 is: P1 = u ^ 2 / R1 = 110x110 / 484 = 25W
The power consumption of bulb L2 is: P2 = u ^ 2 / r2 = 110x110 / 4840 = 2.5W

Two street lamps L1: 110V 100W and L2: 110V 40W are connected in series in a 220 V circuit, and their actual power is calculated
Yes, and a reward of 100 will be offered before 10 o'clock,

The first thing to note here is that the filament resistance is calculated according to the resistance value of normal lighting, which remains unchanged. The actual situation is different. According to P = u ^ 2 / RL1: the resistance of 110V 100W bulb is R1 = u ^ 2 / P1 = 110 ^ 2 / 100 = 121 Ω L2: the resistance of 110V 40W bulb is R2 = u ^ 2 / P2 = 110 ^ 2 / 40 =