The more resistors in series, the less total power the circuit consumes? Doubt! The more the resistance in series, the greater the total resistance of the external circuit. Therefore, the smaller the main circuit current is, so the strain of the terminal voltage = E-IR is also large. Then, the total P = u ^ 2 / R, how to judge the total power reduction? I can't judge it P = e ^ 2 / R refers to the input power of the power supply. I'm talking about the total power consumed by the circuit. P=UI。 First floor, I seem to understand. But if the sum of the series resistances is less than the internal resistance of the power supply, the more series resistances, the less power the circuit consumes?

The more resistors in series, the less total power the circuit consumes? Doubt! The more the resistance in series, the greater the total resistance of the external circuit. Therefore, the smaller the main circuit current is, so the strain of the terminal voltage = E-IR is also large. Then, the total P = u ^ 2 / R, how to judge the total power reduction? I can't judge it P = e ^ 2 / R refers to the input power of the power supply. I'm talking about the total power consumed by the circuit. P=UI。 First floor, I seem to understand. But if the sum of the series resistances is less than the internal resistance of the power supply, the more series resistances, the less power the circuit consumes?

First of all, your question is a little unclear. The total power consumed by the circuit refers to P = ie. the larger the external resistance is, the smaller the current in the circuit is, and the smaller the total power is
What you want to ask is the output power of the power supply, that is, the power consumed by the external circuit, P = IU. Its characteristic is that when the external resistance R = internal resistance R, the maximum is equal to e ^ 2 / 4R, so it can not be said that the higher the resistance, the greater the output power

On the relationship between voltage, resistance and current in physical series circuit
In the series circuit, the resistance decreases, the current increases and the voltage increases. In addition, the voltage is proportional to the resistance, the resistance increases, the current decreases and the voltage increases. So in the series circuit, is the voltage proportional to the resistance or inversely proportional?

In order to answer the questions about voltage, resistance and current in a circuit, we must find out the conditions given by the questions
The current in the series circuit is constant, and the voltage at both ends of the resistance in the circuit is equal to the current * resistance value. Because the current is constant, the greater the resistance value is, the greater the voltage at both ends is. The premise here is that the current is constant
To answer another question, if the voltage at both ends of a circuit is constant, the current = voltage / resistance. Since the voltage is constant, the smaller the resistance, the greater the current
Another formula: current = voltage / resistance. The higher the voltage at both ends of a fixed resistance, the greater the current flowing through the resistance. The premise here is that the resistance does not change
Hope to help you

Students all know that if two bulbs with the same rated voltage and different rated power are connected in parallel to the home circuit, the bulb with higher rated power will light up. If these two bulbs are connected in series to the home circuit, who will light up? Please make a guess and explain the reason

When two bulbs are connected in series, according to the power calculation formula P = I2R, because the current in the series circuit is equal everywhere, the greater the resistance, the greater the actual power, the brighter the bulb. Answer: guess: the bulb with lower rated power is brighter; reason: in the series circuit