The working current of an electric appliance is 0.5 A, and it consumes 66000 J of electric energy in 10 min

The working current of an electric appliance is 0.5 A, and it consumes 66000 J of electric energy in 10 min

Actual power P = w / T = 66000j / 10 * 60s = 110W
Actual voltage U = P / I = 110W / 0.5A = 220V

The current of a consumer with a resistance value of 10 Ω is 0.3 a when it works normally. How to connect it to a circuit with a current of 0.8 a?

If the current I = 0.8A in the circuit is greater than that of the normal operation of the electric appliance, I use = 0.3A, a resistor needs to be paralleled for shunt, ∵ the main current in the parallel circuit is equal to the sum of the currents of each branch, ∵ the current through the resistor: IR = I-I use = 0.8a-0.3a = 0.5A, ∵ the voltage at both ends of each branch in the parallel circuit is equal