A 4-ohm resistor is connected in series with a consumer on a 6V power supply. Now we only know that the actual power of the consumer is 2W, so the current passing through the consumer may be () A 2A B 1A C 0.5A D 0.25A how do I calculate B and C? Are they all right? Is this the question for senior high school entrance examination Big brother and big sister will come and help me. I'm in urgent need. Has anyone seen it? Tell me where it is in the middle school entrance examination

A 4-ohm resistor is connected in series with a consumer on a 6V power supply. Now we only know that the actual power of the consumer is 2W, so the current passing through the consumer may be () A 2A B 1A C 0.5A D 0.25A how do I calculate B and C? Are they all right? Is this the question for senior high school entrance examination Big brother and big sister will come and help me. I'm in urgent need. Has anyone seen it? Tell me where it is in the middle school entrance examination

Let the current through the circuit be I
Then 4 * I + 2 / I = 6V
2I^2-3I+1=0
So I = 1A or 1 = 0.5A
Both B and C are right

A 4 Ω resistor is connected in series with a consumer at both ends of the 6V power supply. Now we only know that the actual power of the consumer is 2W. How much current may pass through the consumer?

Let the current through the consumer be I, ∵ ur = IR = I × 4 Ω, u = pi = 2WI, ∵ u = ur + U = I × 4 Ω + 2WI, which is reduced to 2i2-3i + 1 = 0, ∵ I = 1A or I = 0.5A. A: the current through the consumer may be 1A or 0.5A