When the voltage at both ends of the circuit remains unchanged, the resistance value increases by 2 Ω, and the current becomes 2 / 3 of the original value, what is the original resistance value

Let the original resistance be R Ω and u unchanged
Because I = u / R
So u / (R + 2) = 2 / 3I
U/（R+2）＝2/3（U/R）
U/（R+2）＝2U/3R
3RU＝2U（R+2）
3R＝2（R+2）
3R＝2R+4
3R－2R＝4
R = 4 (Euro)

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When the voltage at both ends of the circuit remains unchanged, the resistance value increases by 2 Ω, and the current becomes 2 / 3 of the original value, what is the original resistance value