An inductive coil is connected to a DC source of u = 120V, I = 20A. If it is connected to an AC source of F = 50 Hz, u = 220 V, I = 28.2a. Calculate the coil resistance and inductance

An inductive coil is connected to a DC source of u = 120V, I = 20A. If it is connected to an AC source of F = 50 Hz, u = 220 V, I = 28.2a. Calculate the coil resistance and inductance

R = U/I = 120/20 = 6R
R+2*pi*f*L=220/28.2 => L =5.7uH

Connect a coil to a 50 Hz, 120 V AC power supply, the current is, the resistance of the coil is r = 6 Ω, then the inductance is L=

The current is? A
If the current is 2a, the inductance L = 190mh,
If the current is 3a, the inductance L = 126mh,
If the current is 6a, the inductance L = 60.7mh

The inductance is 0.032h, the resistance is 10 Ω, two components are connected in series, a) connected to 220 V 50 Hz AC power supply, b) connected to 220 V DC power supply, please analyze the resistance

DC inductance is equivalent to short circuit, I = u / r = 220 / 10 = 22a, u = 220V
AC: use the square root of phasor I = u / Z Z = (10 * 10 + (2 * 3.14 * 50 * 0.032))
Ur=I*R Ul=U-Ur
You can find it