Why is capacitor equivalent to short circuit at the moment of power on?

Why is capacitor equivalent to short circuit at the moment of power on?

Capacitance is equivalent to a container containing electricity. Its impedance to current is capacitive, so it is called capacitive reactance. An important characteristic of capacitive reactance is that it is proportional to the current capacitance. The larger the current capacitance is, the greater the capacitive reactance is, the greater the impedance to current is. The smaller the current capacitance is, the smaller the capacitive reactance is, the greater the impedance to current is

Excuse me electricians, how to discharge the capacitor in an instant? If it is an instant short circuit, is it feasible? (the voltage value is lower than 12V)
This is to discharge the capacitor in the delay lighting circuit, so that the delay time can be determined randomly according to the actual needs
Generally speaking, the control goal is: when you press the first switch, the light goes on, and then press the second switch, the light goes out. I hope you can give me better suggestions. (both switches are turned on instantly and then turned off.)

Yes. The capacitor is usually short circuited directly. Use the lead of the multimeter to short circuit directly or use its screwdriver