There is a bulb with a working voltage of 3 V and a working current of 0.2 A. if it works normally, how many ohm resistor should be connected in series to connect it to the 6 V power supply Can you help me

There is a bulb with a working voltage of 3 V and a working current of 0.2 A. if it works normally, how many ohm resistor should be connected in series to connect it to the 6 V power supply Can you help me

3 / 0.2 = 15 Ω
6 / 0.2 = 30 Ω
30-15 = 15 Ω
15 euro string

After connecting a bulb marked "12V 8W" in series with a resistor to a 12V power supply, the power consumed by the resistor is 2W
For example, the voltage at both ends of a bulb is 4V, the current in B circuit is 0.5A, the size of C resistance is 12 Ω, and the power consumed by D resistance is 2W

Let the internal resistance of the lamp be R1, and the connection resistance be R2P = u ^ 2 / r = > R1 = u ^ 2 / P = 12 * 12 / 8 = 18 ohm. The total resistance of the circuit is R1 + R2. Then I * (R1 + R2) = u = > I * (18 + R2) = 12 -------- 1. The resistance consumption is 2W, and I ^ 2 * R2 = 2 -------- 2

Connect a 12V 6W bulb in series with a resistor and connect it to a 12V power supply. If the resistor consumes 1W of power (filament resistance remains unchanged), the lamp will turn off

The light is dim

Connect a bulb marked "6V 6W" to the power supply, and the actual power of the bulb is 1.5W? (the resistance of the lamp does not change) (2) what is the supply voltage?

(1) The resistance of the bulb: r = U2, P = (6V) 26W = 6 Ω; (2) when the actual power of the bulb is 1.5W, the voltage of the power supply: u = P, r = 1.5W × 6 Ω = 3V