In the home circuit, the filament resistance of an incandescent lamp is 484 ohm when it normally emits light In the home circuit, the filament resistance of an incandescent lamp is 484 ohm when it normally lights up. How much power is consumed by the lamp when it normally lights up for one hour? How much kwh is consumed?

In the home circuit, the filament resistance of an incandescent lamp is 484 ohm when it normally emits light In the home circuit, the filament resistance of an incandescent lamp is 484 ohm when it normally lights up. How much power is consumed by the lamp when it normally lights up for one hour? How much kwh is consumed?

The rated power of the bulb is: P = u ^ 2 / r = (220 V × 200 V) / 484 Ω = 100 W
The power consumption of the lamp for normal lighting for one hour is w = Pt = 100W × 3600s = 360000j = 0.1kwh
Note: 1H = 3600s
1kwh=3.6×10^6J

A constant value resistor marked "10 ohm, 0.5 a" is connected to a 3V power supply, and the current passing through is? Ampere. If it is connected to a 9V power supply circuit, at least one? Ohm resistor needs to be connected in series to work normally? (no figure,

1. According to Ohm's law, current = voltage / resistance
3 V / 10 ohm = 0.3 A, connect it to 3V power supply, the current is 0.3 a
2. 9 V / 10 ohm = 0.9 a, which has exceeded its rated current by 0.5 A. (the resistance will gradually heat up, so that its resistance value may increase at last, and then the temperature will gradually decrease.)
According to Ohm's law, voltage = current * resistance
10 ohm * 0.5 A = 5V, the voltage should not exceed 5V under the current of 0.5 a
9v-5v = 4V, in this case, a series voltage divider is needed, and the voltage divider is 4V
The current is equal in series, 4V / 0.5 A = 8 ohm
Need to series a "8 ohm, 0.5 a" constant resistance can be normal

There is an electrical appliance with a resistance of 20 ohm. When it works normally, the current intensity through it is 0.5 A. (1) when the electrical appliance is connected to a 12 V power supply, it is on
What is the current intensity of the current? Try to analyze whether the electrical appliance can work normally at this time? (2) if it is connected to a 12 volt power supply, how large a resistor needs to be connected in series to make it work normally?

The rated voltage of the consumer should be u = IR = 0.5 × 20 = 10V. When the consumer is connected to a 12V power supply, what is the current intensity through it? I = u / r = 12 △ 20 = 0.6A the current of the consumer exceeds the normal current, which is in danger of burning. If the consumer is connected to a 12V power supply, it needs to connect one in series to make it work normally

The resistance of an electrical appliance is 10 Ω and the power is 100W. Please calculate its current and voltage

It mainly depends on whether a consumer is a pure resistance circuit. Pure resistance circuit: electrical components only emit light and heat. For example, a lamp, an electric stove, and a TV can make sound instead of a TV
If it's a pure resistance circuit, that's good. 100 divided by 10 is the current. 100 multiplied by 10 is the voltage
The basic formula is power = current squared * resistance = voltage squared divided by resistance